Numbering System Conversions

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May 15th, 2023

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#include <bits/stdc++.h>
using namespace std;
long long decimalToBinary(int n);
string binaryToHex(string binary);
long long OctalToBinary(int num);
int BinaryToDecimal(string BinaryNum);
int OctalToDecimal(int num);
int convertBinarytoOctal(long long binaryNumber);
long long DecimalToOctal(long long decimal);
string binaryToHex(string binary)
{
// 1 1 1 0
// 2^3 2^2 2^1 2^0
// 8*1 + 4*1 + 2*1 + 0
// 14 >> 'E'
char arr[16] = {'0', '1', '2', '3', '4', '5', '6', '7', '8', '9', 'A', 'B', 'C', 'D', 'E', 'F'};
vector<char> hex;
string part1 = ""; // binary number before '.' , if binary="1001.1101" >> part1="1001"
string part2 = ""; // binary number after '.' , if binary="1001.1101" >> part2="1101"
for (int i = 0; i < binary.length(); i++)
{
if (binary[i] == '.')
{
part2 = binary.substr(1 + binary.find('.'), binary.length());
break;
}
part1 += binary[i];
}
if (part1.length() > 0)
{
int sum = 0, j = 0;
reverse(part1.begin(), part1.end());
for (int i = 0; i < part1.length(); i++)
{
sum += (part1[i] - '0') * (pow(2, j));
j++;
if (j == 4)
{
hex.push_back(arr[sum]);
sum = 0;
j = 0;
}
}
if (sum != 0)
{
hex.push_back(arr[sum]);
}
reverse(hex.begin(), hex.end());
}
if (part2.length() > 0)
{
hex.push_back('.');
int sum = 0, j = 3;
for (int i = 0; i < part2.length(); i++)
{
sum += (part2[i] - '0') * (pow(2, j));
j--;
if (j == -1)
{
hex.push_back(arr[sum]);
sum = 0;
j = 3;
}
}
if (sum != 0)
{
hex.push_back(arr[sum]);
}
}
string res = ""; // Hexadecimal number
for (int i = 0; i < hex.size(); i++)
{
res += hex[i];
}
return res;
}
long long OctalToBinary(int num)
{
int decimal = OctalToDecimal(num);
return decimalToBinary(decimal);
}
int BinaryToDecimal(string BinaryNum)
{
int sz = (int)BinaryNum.size();
int DecimalNum = 0;
for (int i = 0; i < sz; i++)
{
if (BinaryNum[sz - 1 - i] == '1')
DecimalNum += pow(2, i);
}
return DecimalNum;
}
int OctalToDecimal(int num)
{
int x = 0;
int result = 0;
while (num > 0)
{
int y = num % 10; // The right-most digit
num /= 10;
result += y * pow(8, x);
++x;
}
return result;
}
int convertBinarytoOctal(long long binaryNumber)
{
int octalNumber = 0, decimalNumber = 0, i = 0;
while (binaryNumber != 0)
{
decimalNumber += (binaryNumber % 10) * pow(2, i);
++i;
binaryNumber /= 10;
}
i = 1;
while (decimalNumber != 0)
{
octalNumber += (decimalNumber % 8) * i;
decimalNumber /= 8;
i *= 10;
}
return octalNumber;
}
long long DecimalToOctal(long long decimal)
{
long long digit = 1;
long long decNum = decimal;
long long octal = 0;
while (decimal != 0)
{
octal += (decimal % 8) * digit;
digit *= 10;
decimal /= 8;
}
return octal;
}
long long decimalToBinary(int n)
{
long long ans = 0;
int remainder, i = 1;
while (n != 0)
{
remainder = n % 2;
ans += remainder * i;
i = i * 10;
n = n / 2;
}
return ans;
}
int main()
{
char c = 'y';
cout << "******************** Number Base Conversion *********************\n";
while (c == 'y')
{
int num;
cout << "1.Binary to Decimal\n2.Binary to Octal\n3.Binary to Hexadecimal\n4.Decimal to Binary\n5.Decimal to Octal\n6.Octal to Binary\n7.Octal to Decimal\nYour choice : " << endl;
cin >> num;
if (num == 1)
{
cout << "Enter Binary number to convert into its Decimal : ";
string s;
cin >> s;
cout << "Decimal Number of ( " << s << " ) is ( " << BinaryToDecimal(s) << " )" << endl;
}
if (num == 2)
{
cout << "Enter Binary number to convert into its Octal : ";
long long s;
cin >> s;
cout << "Octal Number of ( " << s << " ) is ( " << convertBinarytoOctal(s) << " )" << endl;
}
if (num == 3)
{
cout << "Enter Binary number to convert into its Hexadecimal : ";
string s;
cin >> s;
cout << "Hexadecimal Number of ( " << s << " ) is ( " << binaryToHex(s) << " )" << endl;
}
if (num == 4)
{
cout << "Enter Decimal number to convert into its Binary : ";
int s;
cin >> s;
cout << "Binary Number of ( " << s << " ) is ( " << decimalToBinary(s) << " )" << endl;
}
if (num == 5)
{
cout << "Enter Decimal number to convert into its Octal : ";
long long s;
cin >> s;
cout << "Octal Number of ( " << s << " ) is ( " << DecimalToOctal(s) << " )" << endl;
}
if (num == 6)
{
cout << "Enter Octal number to convert into its Binary : ";
int s;
cin >> s;
cout << "Binary Number of ( " << s << " ) is ( " << OctalToBinary(s) << " )" << endl;
}
if (num == 7)
{
cout << "Enter Octal number to convert into its Decimal : ";
int s;
cin >> s;
cout << "Decimal Number of ( " << s << " ) is ( " << OctalToDecimal(s) << " )" << endl;
}
cout << "\nperform another operation (y/n) : ";
cin >> c;
}
}

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