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ThegeekKnight16

Big Prize

Jul 2nd, 2024
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C++ 1.87 KB | None | 0 0
  1. #include <bits/stdc++.h>
  2. #include "prize.h"
  3. using namespace std;
  4. map<int, vector<int>> ans;
  5.  
  6. vector<int> query(int x)
  7. {
  8.     if (ans.count(x)) return ans[x];
  9.     return ans[x] = ask(x);
  10. }
  11.  
  12. int dc(int ini, int fim, int qMen, int qL, int qR)
  13. {
  14.     //Cases in which i don't have to test
  15.     if (ini > fim || qL + qR == qMen) return -1;
  16.     if (fim - ini <= 1)
  17.     {
  18.         vector<int> aL = query(ini), aR = query(fim);
  19.         if (aL[0]+aL[1] == 0) return ini;
  20.         if (aR[0]+aR[1] == 0) return fim;
  21.         return -1;
  22.     }
  23.     if (query(ini) == query(fim)) return -1;
  24.  
  25.     //all of them are expensive
  26.     if (fim - ini + 1 == qMen - (qL + qR))
  27.     {
  28.         for (int i = ini; i <= fim; i++)
  29.         {
  30.             vector<int> a = query(i);
  31.             if (a[0]+a[1] == 0) return i;
  32.         }
  33.         return -1;
  34.     }
  35.  
  36.     //get middle expensive
  37.     int mL = (ini+fim)>>1, mR = (ini+fim)>>1;
  38.     vector<int> aL, aR;
  39.     while (mL >= ini)
  40.     {
  41.         aL = query(mL);
  42.         if (aL[0]+aL[1] == 0) return mL;
  43.         if (aL[0]+aL[1] < qMen) --mL;
  44.         else break;
  45.     }
  46.     while (mR <= fim)
  47.     {
  48.         aR = query(mR);
  49.         if (aR[0]+aR[1] == 0) return mR;
  50.         if (aR[0]+aR[1] < qMen) ++mR;
  51.         else break;
  52.     }
  53.  
  54.     //then divide and conquer
  55.     int x = dc(mR, fim, qMen, aR[0], qR);
  56.     if (x == -1) return dc(ini, mL, qMen, qL, aL[1]);
  57.     return x;
  58.  
  59. }
  60.  
  61. int find_best(int n)
  62. {
  63.     //here to find expensive quantity -> P(expensive) ≃ 1/sqrt(N)
  64.     mt19937 rng(chrono::steady_clock::now().time_since_epoch().count());
  65.     vector<int> ids;
  66.     for (int i = 0; i < 10; i++) ids.push_back(uniform_int_distribution<int>(0, n-1)(rng));
  67.     vector<vector<int>> possQ;
  68.     for (auto x : ids) possQ.push_back(query(x));
  69.     int qMen = 1;
  70.     for (auto &x : possQ) qMen = max(qMen, x[0]+x[1]);
  71.  
  72.     return dc(0, n-1, qMen, 0, 0);
  73. }
  74.  
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